Problem 1 of 3 · warm-up
In Al + 3Ag+ → Al3+ + 3Ag, which reactant is oxidized?
Hint 1 · the clue
An electron-transfer reaction is given.
Hint 2 · the next move
Asking which reactant is oxidized means tracking oxidation numbers: the one whose number goes up loses electrons.
Your path:
- Assign oxidation numbers on both sides
- Al: 0 → +3, number goes up
- Going up means oxidized
Answer
Answer: Al
Full worked solution
What you know: Al + 3Ag+ → Al3+ + 3Ag. What you want: the reactant that is oxidized.
- Assign oxidation numbers. An element alone is 0, and a monatomic ion has its ion charge.
- Track Al: 0 → +3. It increases, so Al loses 3 electrons. That is oxidation.
- Track Ag: +1 → 0. It decreases, so Ag+ gains electrons. That is reduction.
- The oxidized reactant is Al.
Check: Electrons lost equal electrons gained: Al loses 3, and 3 Ag+ each gain 1.
Watch out: Losing electrons makes the number go up, not down. Electrons are negative.
Your route: Compare oxidation numbers → Increase means oxidation
On the periodic table: Aluminum (Al) is in Group 13 and loses 3 electrons, so it forms Al³⁺.
Answer: Al
YOUR PERIODIC-TABLE REFERENCE
Atomic number identifies proton count. The decimal mass is an average, not an isotope’s mass number. Use supplied rounded masses when a problem gives them.
